Between numbers 3 and 80 find another 10 natural numbers that alltogether be consecutive terms of arithmetic progression.
80=3+(n-1)d
80=3+(12-1)d
80=3+11d
77=11d
d=77/11
d=7
3,10,17,24,31,38,45,52,59,66,73,80
Number series for competitive exams Can you complete the following number series?
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