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Consecutive terms of arithmetic progression

 Between numbers 3 and 80 find another 10 natural numbers that all
together be consecutive  terms of arithmetic progression.

 


 80=3+(n-1)d

80=3+(12-1)d

80=3+11d

77=11d

d=77/11

d=7

3,10,17,24,31,38,45,52,59,66,73,80

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